Alternatively
5 - 12x = 8 - 7x - [6/(3 (2+5³) + 5x)]
5 - 12x = 8 - 7x - [6/(3 (127) + 5x)]
5 - 12x = 8 - 7x - 6/(381 + 5x)
5(381 + 5x) - 12x(381 + 5x) = 8(381 + 5x) - 7x(381 + 5x) - 6
1905 + 25x - 4572x - 60x^2 = 3048 + 40x - 2667x + 35x^2 - 6
1905 -4547x - 60x^2 = 3042 - 2627x +35x^2
1905 - 3042 - 4547x + 2627x - 60x^2 - 35x^2 = 0
-1137 - 1920x -95x^2 = 0
1137 + 1920x + 95x^2 = 0
Then I gave up
You have to put the equation in the correct formula:
aX² + bX + c = 0
Which would be 95X² + 1920X + 1137 = 0
Then factorize them (not sure if it's possible with these particular numbers, though).
5-12x = 8-7x-[6/3(2+5^3)+5x]
5-12x+7x = 8-[6/3(127)+5x]
5-5x = 8-[254+5x]
5-8-5x = -254+5x
-3-5x = -254+5x
-5x = -254+3+5x
-10x = -251
x = 25.1
Knowing me there's a glaring fault in there somewhere, but *shrugs* [/2 cents].
There. It should have been -254-5X (the -ve sign would change everything inside the bracket into a negative). Fell for the same trick before myself. XD
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