• Welcome to Religious Forums, a friendly forum to discuss all religions in a friendly surrounding.

    Your voice is missing! You will need to register to get access to the following site features:
    • Reply to discussions and create your own threads.
    • Our modern chat room. No add-ons or extensions required, just login and start chatting!
    • Access to private conversations with other members.

    We hope to see you as a part of our community soon!

Math Question

Shadow Wolf

Certified People sTabber
Still curious though, what's the right answer to that equation according to your teacher/textbook?
The answer in the book is simply Ø.
Working it out again I got Ø = 60.5, but all is needed is the Ø and I'm not sure if the 60.5 is right because I haven't had any problems like this one in my previous math classes. But I also skipped the last of the remedial math classes my school offers because I'm running out of financial aid.
Actually other than this one particular problem I've not had any issues, even working a week ahead and reviewing the practice test for the first test.
 
Last edited:

Koldo

Outstanding Member
The answer in the book is simply Ø.
Working it out again I got Ø = 60.5, but all is needed is the Ø and I'm not sure if the 60.5 is right because I haven't had any problems like this one in my previous math classes.

Write down here how you reached that result (Ø = 60.5) and i will check it.
 

Shadow Wolf

Certified People sTabber
5-12x=8-7x-[6÷3(2+5³)+5x]
5-12x=8-7x-[6÷3(127)+5x]
5-12x=8-7x-[6÷381+5x]
5-12x=8-7x-[63.5+5x]
5-12x=8-7x-63.5-5x
-12x+5=-12x-55.5
Ø=60.5

One thing I have noticed is there seems to be some inconsistencies between here and what I've been taught on order of operations. What I have been taught is to do in this order: Parentheses, exponents, multiplication, division, addition, subtraction. Which it makes a big difference dividing 381 by 6 or by 2.
 

Phasmid

Mr Invisible
5-12x=8-7x-[6÷3(2+5³)+5x]
5-12x=8-7x-[6÷3(127)+5x]
5-12x=8-7x-[6÷381+5x]
5-12x=8-7x-[63.5+5x]
5-12x=8-7x-63.5-5x
-12x+5=-12x-55.5
Ø=60.5

One thing I have noticed is there seems to be some inconsistencies between here and what I've been taught on order of operations. What I have been taught is to do in this order: Parentheses, exponents, multiplication, division, addition, subtraction. Which it makes a big difference dividing 381 by 6 or by 2.

It's not 3(127). If you wish to multiply by the division you add the multiplied value to the numerator. So 6/3(127) =(6(127))/3
 

Debater Slayer

Vipassana
Staff member
Premium Member
5-12x=8-7x-[6÷3(2+5³)+5x]
5-12x=8-7x-[6÷3(127)+5x]
5-12x=8-7x-[6÷381+5x]
5-12x=8-7x-[63.5+5x]
5-12x=8-7x-63.5-5x
-12x+5=-12x-55.5
Ø=60.5

One thing I have noticed is there seems to be some inconsistencies between here and what I've been taught on order of operations. What I have been taught is to do in this order: Parentheses, exponents, multiplication, division, addition, subtraction. Which it makes a big difference dividing 381 by 6 or by 2.

According to Wolfram, division is done first in this one. Sometimes you'd have the option to do both simultaneously, since they wouldn't be conflicting together as in this particular question.

If I were to stick to one solution though, I'd go with the one I posted first (which Wolfram Alpha agrees with, too :D).

ETA: Yes, now it's certain: you divide 6 by 3 first, since in the right order, we work from left to right. If you were to multiply the 3 by (127) instead of dividing 6 by 3, you'd break the order of operation and hence will arrive at a wrong answer.

Good luck with your maths classes! :)
 
Last edited:

Koldo

Outstanding Member
5-12x=8-7x-[6÷3(2+5³)+5x]
5-12x=8-7x-[6÷3(127)+5x]
5-12x=8-7x-[6÷381+5x]
5-12x=8-7x-[63.5+5x]
5-12x=8-7x-63.5-5x
-12x+5=-12x-55.5
Ø=60.5

There are two important things to say here.

First: If just the 3 is under the 6, you can't multiply the 3 with 127. This is because 127 in itself is equal to 127/1, and if you are going to multiply a fraction you have to multiply the numbers "above" and the numbers "below" separately. A simple example would be 2/3*3, which is the same as 2/3*3/1. We multiply 2 by 3, and 3 by 1. The result is 6/3, which is the same as 2.

It may be easier to understand this if i write it such as:

1i6ma.jpg


We multiply the numbers "above" with the other numbers "above", and the numbers "below" with the numbers "below".

In this math problem, it would be 6*127 and 3*1. The result is 762/3, which is equal to 254.

Check it out:

sgk0wh.jpg


However, this is a longer road to reach the result.
If you divide 6 per 3 in itself, the result is 2.
2*127 is equal to 254.
I will explain why you can do this down below, in the second part of my post.

DO keep attention that i am considering that only 3 is under the 6.

Second: the number you ( incorrectly) reached was 6/381, and when you did the division you came to the result 63.5. The problem here is that it is the 6 being divided by 381, and not the inverse. 6 divided by 381 is equal to 0,0157.

6 = 0,0157
381

One thing I have noticed is there seems to be some inconsistencies between here and what I've been taught on order of operations. What I have been taught is to do in this order: Parentheses, exponents, multiplication, division, addition, subtraction. Which it makes a big difference dividing 381 by 6 or by 2.

Actually, the order is more like: parentheses, exponents, multiplication/division,addition/subtraction.

The slashes are important, because otherwise you would think that multiplication takes precedence over division, and this is not true.

In this particular case, the parentheses was just a leftover.
In this sort of math problem, when you reach a single number inside a parathenses, it is the same as if you didn't have a parantheses anymore.

Examples:
10 * ( 30 ) is the same thing as 10 * 30.
5 * ( 2 ) is the same thing as 5 * 2.

And as such, the number inside the parentheses loses its priority.
Going back to the original problem:

6/3*(127) is the same thing as 6/3*127.

So we have a division AND a multiplication here, and you can solve this in whatever order you prefer. I highly recommend you to always solve divisions first WHEN you have a "clear" division, such as: 6/3, 81/9,49/7, and so on. This is simply because you will have to handle smaller numbers.

Example:
25 * 99
5

If you divide first ( which will take you a mere second ) you will end up with 5 * 99. 5*99=495. This is pretty simple.
If you multiply first ( which will take you many seconds ) you will end with 2475/5. And you will have yet to divide those numbers ( which takes several more seconds ) to end up with 495.
The result is the same, but one way is quicker and easier to do.
 
Last edited:

JakeWible

New Member
Yeah even I am curious to know the answer now,after seeing all fop your lengthy calculations.After seeing all of your calculation seems I have forgotten my general maths concepts.
 

DawudTalut

Peace be upon you.
I have a math problem on my homework and there are two parts I'm not sure what to do with.
5-12x=8-7x-[6/3(2+5^3)+5x]
What I'm not sure how to do is do I multiple 5 to the third, then that number times 3, or 3*5, and then that number (15) to the third? I'm also not sure how to simplify with a division sign.

5-12x=8-7x-[6/3(2+5^3)+5x]

5-12x=8-7x-[6/3(2+125) + 5x]

5-12x=8-7x-[6/3(127) + 5x]

5-12x= 8-7x- [6/381 + 5x]

381 [ 5 -12x ] = 381 [8 - 7x - {6/381 + 5x } ]

381(5) - 381(12X) = 381(8) - 381(7X) - 381{6/381 + 5x }

1905 - 4572x = 3048 - 2667x - 6 - 1905x

-4572X + 2667X + 1905X = 3048 - 6 - 1905

{-4572 + 2667 + 1905}x = 1137


0x = 1137

x = 1137 / 0

EXPLANATION

A) In general, a single value can't be assigned to a fraction where the denominator is 0 so the value remains undefined (see below for other applications).

B)
In calculus
As with any formal calculation, invalid results may be obtained. A logically rigorous (as opposed to formal) computation would assert only that


3fad4eddb9cbd9b39e1f937fd53aa648.png


More
@
Division by zero - Wikipedia, the free encyclopedia



 
Last edited:

randi

New Member
I was also in this problem but I got it after a lot of time.However I want someone to do my math homework but couldn't find here and there. after such a long time I realized that it is possible by me but take time and my examination is knocking at the door.
 

Jedster

Well-Known Member
5-12x = 8-7x-[6/3(2+5^3)+5x]

5-12x+7x = 8-[6/3(127)+5x]

5-5x = 8-[254+5x]

5-8-5x = -254+5x

-3-5x = -254+5x

-5x = -254+3+5x

-10x = -251

x = 25.1

Knowing me there's a glaring fault in there somewhere, but *shrugs* [/2 cents].

Your error was in the line marked in red, the +5 should be -5x.

5-12x=8-7x-[6/3(2+5^3)+5x]

using PEDMAS(https://www.mathsisfun.com/operation-order-pemdas.html),
first get rid of brackets, innermost first
[6/3(2+5^3)+5x] = [6/3(2+125)+5x]
= [6/3(127)+5x]
= [6/3*127+5x]
= [2*127+5x]
=[254 + 5x], so original equation becomes
5-12x = 8-7x-[254 + 5x]
5-12x = 8-7x-254 -5x
5-12x = 8-7x-254 -5x

5-12x = -248 -12x therefore

5= -248 inpossible, so ....therefore there are no solutions

also the rhs and lhs represent parallel lines that(obviously) never meet
 

Luciferi Baphomet

Lucifer, is my Liberator
I have a math problem on my homework and there are two parts I'm not sure what to do with.
5-12x=8-7x-[6/3(2+5^3)+5x]
What I'm not sure how to do is do I multiple 5 to the third, then that number times 3, or 3*5, and then that number (15) to the third? I'm also not sure how to simplify with a division sign.
omfg that looks so hard.
 

Truth&Hope

Jesus Freak
I have a math problem on my homework and there are two parts I'm not sure what to do with.
5-12x=8-7x-[6/3(2+5^3)+5x]
What I'm not sure how to do is do I multiple 5 to the third, then that number times 3, or 3*5, and then that number (15) to the third? I'm also not sure how to simplify with a division sign.
To do the problem correctly, you must know the order of operations. PEMDAS
Parentheses
Exponents
Multiplication (left to right)
Division (left to right)
Addition (left to right)
Subtraction (left to right)
Do one function at a time
Inside the parentheses the exponent must be done first. When the functions are completed then isolate the letter (x) on the left and the number (value) on the right (of the equal sign). So 5x5x5 (125).
 
Top