The Sum of Awe
Brought to you by the moment that spacetime began.
I’m very confused about the Monte Hall problem.The easiest way I've heard to explain the Monte Hall problem is that when you make your first choice, you have a 1/3 probability of being right and a 2/3 probability of being wrong. Once the other box is opened, if you switch, you are betting that your first choice was wrong.
Even with that explanation, even though you were 2/3 wrong on your initial choice, there was always going to be two duds of the three, why does it make a difference if one is exposed? It becomes 50/50 either way.
If Monte knows what is behind the curtains, he’ll reveal a dud regardless of whether you hold the big prize or not. Revealing a dud does not change the probability that you have either a dud or a prize, because your 1/3 choice was out of his control.