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#1
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Okay, here's what I don't understand. If something loses half it's carbon in 5,700 years wouldn't logic say that in 11,400 all of it would be gone? Why would the process slow to half the speed that it was originally decaying at? And if the above were true, wouldn't that mean, if we cannot find anything that used to be alive completely devoid of carbon, that the world is less than 11,400 years old or at least all life on the earth is that young? Someone please explain this reasoning to me.
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"Do unto others as you would have them do unto you" --- The wisest words ever spoken. |
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#2
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Pour a cup of sugar into a bowl and place it on the counter. Every morning, upon waking, remove exactly one half the sugar. Let me know when it's all gone ...
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if G-d ( G-d is not 'X' for all 'X' )
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#3
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I haven't the faintest clue, but I'll pray you!
![]() How dreadfully painstakingly boring; but a good point!
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My life is an open book; if you don't like the read, put me back on the shelf ....................
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#4
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It's interesting to note that starting with two cups would be no more or less boring.
By the way: I've missed you. I hope you're well.
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if G-d ( G-d is not 'X' for all 'X' )
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#5
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I still don't get it, why every 5,700 years. If you keep pouring the cup of sugar on the table at the same speed it's your choice to stop at half and do half the next day. Why would it stop and half itself every 5,700 years?
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"Do unto others as you would have them do unto you" --- The wisest words ever spoken. |
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#6
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Quote:
Quote:
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We would rather be ruined than changed; We would rather die in our dread Than climb the cross of the moment And let our illusions die |
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#7
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okay, now how did they come up with 5,730 years? No human being has lived that long. How was it discovered in the first place and can anything manipulate the rate of decay?
__________________
"Do unto others as you would have them do unto you" --- The wisest words ever spoken. |
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#8
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Quote:
ln(A)=-kt-H0(A), where A is concentration of product (or reactant), t is time, and k is the rate constant. Determining the rate constant is possible from experimentation, but it is a painful process. Measuring concentrations is a royal pain in the ***. Long half lives are pretty easy to measure compared to smaller versions, which necessarily decay more rapidly. The half life of a first order reaction is constant, and can be calculated from k with no trouble at all. ln(2)/k. K is the same as the above equation. edit: A simpler way to look at this is to examine the equaton y=1/2^X. The resulting graph approaches zero, but will never reach it. And to answer your question, there is no way to alter the process of radioactive decay.
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Don't worry about people stealing your ideas. If your ideas are any good, you'll have to ram them down people's throats. ~Howard Aiken Last edited by yossarian22; 04-16-2008 at 11:58 AM. |
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#9
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You mean long half lives as in, something that is newer versus something that is older right?
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"Do unto others as you would have them do unto you" --- The wisest words ever spoken. |
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#10
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I don't understand all the symbols in equations can you put it into + x - a |